MI Review | Constants 1 Periodi Consider the dissolution of AgBr in water at 25 'C:...
Consider the following Gibbs energies at 25 "C Substance Ag (aq) Cr(aq) AgCI(s) Br(aq) AgBr(s) 77.1 - 131.2 - 109.8 - 104.0 -96.9 (a) Calculate AG rn for the dissolution of AgCl(s). (b) Calculate the solubility-product constant of AgCl Number Number kJ mol (c) Calculate Δ3rxn for the dissolution of AgBr(s). (d) Calculate the solubility-product constant of AgBr Number Number kJ mol
Consider the Gibbs energies at 25 ∘C. SubstanceSubstance ΔG∘f (kJ⋅mol−1)ΔGf∘ (kJ·mol−1) Ag+(aq)Ag+(aq) 77.177.1 Cl−(aq)Cl−(aq) −131.2−131.2 AgCl(s)AgCl(s) −109.8−109.8 Br−(aq)Br−(aq) −104.0−104.0 AgBr(s)AgBr(s) −96.9−96.9 (a) Calculate ΔG∘rxn for the dissolution of AgCl(s)AgCl(s). kJ⋅mol−1 (b) Calculate the solubility-product constant of AgCl. K= (c) Calculate ΔG∘rxnΔGrxn∘ for the dissolution of AgBr(s)AgBr(s). kJ⋅mol−1kJ⋅mol−1 (d) Calculate the solubility-product constant of AgBr. K=K=
Consider the Gibbs energies at 25 'C AGi (kJ mol) Substance Ag (aq) 77.1 CI (aq) -131.2 AgCls) -109.8 Br (aq) -104.0 -96.9 AgBr(s) (a) Calculate AGn for the dissolution of AgC1(s) kJ mol (b) Calculate the solubility-product constant of AgCl. K = (c) Calculate AGxn for the dissolution of AgBr(s). kJ mol (d) Calculate the solubility-product constant of AgBr. K =
< Question 13 of 18 > Consider the Gibbs energies at 25 °C. Substance AG (kJ. mol-!) Ag+ (aq) 77.1 Cl(aq) -131.2 AgCl(s) -109.8 Br" (aq) -104.0 AgBr(s) -96.9 (a) Calculate AGran for the dissolution of AgCl(s). kJ. mol- (b) Calculate the solubility-product constant of AgCl. kJ. mol- (b) Calculate the solubility product constant of AgCl. K = Enter numeric value (c) Calculate AGtx for the dissolution of AgBr(s). kl. mol-? (d) Calculate the solubility-product constant of AgBr. K=
Part c and d are incorrect Consider the following Gibbs energies at 25°C. AG (kJ mo (aq) cr(aq) AgCI(s) Br(aq) 77.1 -131.2 -109.8 -104.0 -96.9 (a) Calculate Δ. , for the dissolution of AgCl(s) (b) Calculate the solubility-product constant of AgCL Number Number 55.7 kJ mol K-11 1.745 × 10-10 (c) Calculate Δ.in for the dissolution of AgBr(s). (d) Calculate the solubility-product constant of AgBr. Number Number 82.9 kJ mol K2.996x 10 I O Previous Gve Up & View Solution...
Exercise 19.65 Use tabulated half-cell potentials to calculate AG for each of the following reactions at 25 C. Part A Pb2+ (aq) +Mg(e)-Pb(a) +Mg (aq) VAZD AGn Submit Request Answer Part B Br ()+2Cl (aq)-+2Br (aq) + Cl( Express your answer using two significant figures AG Submit Request Answer Part C MnO2(a)+ 4H (aq) + Cu()Mn (ag) +2H,O( Express your answer using two significant figures
Review | Constants Periodi A 135-ml sample of an 8.9 M NaCl solution is diluted to 2.5 L Part A What volume of the diluted solution contains 11.8 g of NaCl? (Hint Figure out the concentration of the diluted solution first.) Express your answer using two significant figures. VO AXD 4.2 L Previous Answers Request Answer Submit
calculate the equilibrium constants at 25∘C for each of the following reactions. 2 CO(g) + O2(g) = 2 CO2(g) Express your answer using two significant figures. IVO ALQ R o a ? K = Submit Request Answer Part B 2 H2S(9) = 2 H2(g) + S2(g) Express your answer using two significant figures. CO ALQ O ?
Exercise 18.102 Review Constants l Periodic Table Part A The solubility of AgCI(s) in water at 25 Cis 1.33 x 10 s mol/L and its AH of solution is 65.7 kJ/mol What is its solubility at 44.4°C? Express your answer using two significant figures x®X5b返返 6.52 10- Request Answer Prev ious Answers Submit Incorrect; Try Again; 14 attempts rema Exercise 18.102 Review Constants l Periodic Table Part A The solubility of AgCI(s) in water at 25 Cis 1.33 x 10...
Question 22 (5 points) Given the following half reactions: - AgBr(s) + e- Ag+ (aq) + e- Ag(s) + Br- (aq) E° = 0.07V → Ag (s) E° = 0.80V - Calculate the Ksp for PbSO4 at 25 degrees C. Please enter your answer in scientific notation, such as 1.2E10 or 1.2E-10 and keep two significant figures.