< Question 13 of 18 > Consider the Gibbs energies at 25 °C. Substance AG (kJ....
Consider the Gibbs energies at 25 'C AGi (kJ mol) Substance Ag (aq) 77.1 CI (aq) -131.2 AgCls) -109.8 Br (aq) -104.0 -96.9 AgBr(s) (a) Calculate AGn for the dissolution of AgC1(s) kJ mol (b) Calculate the solubility-product constant of AgCl. K = (c) Calculate AGxn for the dissolution of AgBr(s). kJ mol (d) Calculate the solubility-product constant of AgBr. K =
Consider the following Gibbs energies at 25 "C Substance Ag (aq) Cr(aq) AgCI(s) Br(aq) AgBr(s) 77.1 - 131.2 - 109.8 - 104.0 -96.9 (a) Calculate AG rn for the dissolution of AgCl(s). (b) Calculate the solubility-product constant of AgCl Number Number kJ mol (c) Calculate Δ3rxn for the dissolution of AgBr(s). (d) Calculate the solubility-product constant of AgBr Number Number kJ mol
Consider the Gibbs energies at 25 ∘C. SubstanceSubstance ΔG∘f (kJ⋅mol−1)ΔGf∘ (kJ·mol−1) Ag+(aq)Ag+(aq) 77.177.1 Cl−(aq)Cl−(aq) −131.2−131.2 AgCl(s)AgCl(s) −109.8−109.8 Br−(aq)Br−(aq) −104.0−104.0 AgBr(s)AgBr(s) −96.9−96.9 (a) Calculate ΔG∘rxn for the dissolution of AgCl(s)AgCl(s). kJ⋅mol−1 (b) Calculate the solubility-product constant of AgCl. K= (c) Calculate ΔG∘rxnΔGrxn∘ for the dissolution of AgBr(s)AgBr(s). kJ⋅mol−1kJ⋅mol−1 (d) Calculate the solubility-product constant of AgBr. K=K=
Part c and d are incorrect Consider the following Gibbs energies at 25°C. AG (kJ mo (aq) cr(aq) AgCI(s) Br(aq) 77.1 -131.2 -109.8 -104.0 -96.9 (a) Calculate Δ. , for the dissolution of AgCl(s) (b) Calculate the solubility-product constant of AgCL Number Number 55.7 kJ mol K-11 1.745 × 10-10 (c) Calculate Δ.in for the dissolution of AgBr(s). (d) Calculate the solubility-product constant of AgBr. Number Number 82.9 kJ mol K2.996x 10 I O Previous Gve Up & View Solution...
Consider the following Gibbs energies at 25 degree C. Calculate Delta G degree _rxn for the dissolution of AgCl(s). Calculate the solubility-product constant of AgCl. K = Calculate Delta G degree_rxn for the dissolution of AgBr(s). Calculate the solubility-product constant of AgBr. K =
gibbs energy Consider the following Gibbs energies at 25 degree C.(a) Calculate Delta G degree rxn for the dissolution of AgCl(s). (b) Calculate the solubility-product click to edit AgCl, Number Number kJ.mol^-1 K= (C) Calculate Delta G degree rxn for the dissolution of AgBr(s). (d) Calculate the solubility-product constant of AgBr. Number Number kJ.mol^-1 K= gibbs energy
Please show work Consider the following Gibbs energies at 25 degree C. calculate delta G degree _rxn for the dissolution of AgCl(s). Calculate the solubility-product constant of AgCl. Calculate delta G degree_rxn for the dissolution of AgBr(s). Calculate the solubility-product constant of AgBr.
Calculate the standard change in Gibbs free energy, AG , for the given reaction at 25.0 "C. Consult the table of thermodynamic properties for standard Gibbs free energy of formation values. NH, CI() = NH(aq) + Cl" (aq) AGxn = kJ/mol Determine the concentration of NH(aq) if the change in Gibbs free energy, AGx. for the reaction is -9.39 kJ/mol. INH1 = Thermodynamic Properties at 298 K So 0 1 ΔΗ kJ/mol 0 105.8 -31.1 -32.6 -100.4 -127.0 -61.8 -124.4...
Calculate the standard change in Gibbs free energy for the reaction at 25 °C. Standard Gibbs free energy of formation values can be found in this table. 3H2(g) + Fe,0,($) 2Fe(s) + 3 H,0 () AGran kJ/mol Thermodynamic Properties at 298 K S° Substance Ag(s) Ag+(aq) Ag2O(s) Ag2S(s) AgBr(s) AgCl(s) AgI(S) AgNO3(s) Al(s) Al2O3(s) AlCl3(s) Ar(9) As(s) As2O5(s) AsCl3(1) Au(s) Ba(s) BaCl2(s) BaCO3(s) Bao(s) BaSO4(s) B(s) B203(s) AH kJ/mol 0 105.8 -31.1 -32.6 -100.4 -127.0 -61.8 -124.4 0 -1675.7 -704.2...
MI Review | Constants 1 Periodi Consider the dissolution of AgBr in water at 25 'C: AgBr(s) = Ag+ (aq) + Br-(aq) Part B Substance AH' S and State kJ/mol J/(K.mol) Ag' (aq) 105.6 72.7 Br (aq) –121.5 82.4 AgBr(s) -100.4 107.1 Calculate Ksp for AgBr at 25°C. Express your answer to two significant figures. VA ALQ O 2 ? KE Submit Request Answer Part C Calculate AG for the dissolution of AgBr at 25°C when [Ag+] = [Br") –...