step by step please TT1 pts Consider the reaction: NHą (g) + HCI (g) → NH,CI...
step by step for both please T71 pts Consider the reaction: NH, (g) + HCI (9) ► NH,CI (s) Given the following table of thermodynamic data at 298 ok: Substance by admons Imoly NH HCI NHCI 4 6.19 -92.30 -314.4 192.5 186,69 94.6 The value of K for the reaction at 25°C is 150 1.4 x 10 1.1 x10-16 9.3 x1095 8.4 x109 Question 2 1/1 pts The equilibrium constant for the following reaction is 5.0 x 10% at 25°C....
Consider the reaction: NH3 (g) + HCl (g) → NH4Cl (s) Given the following table of thermodynamic data at 298 K: Substance! AH/M/mol) I s。(J/K-mol) NH3 g) HCI (g) NHCI)-3144 -46.19 -92.30 192.5 186.69 94.6 The value of K for the reaction at 25 °c is
26. Consider the reaction: (5 pt) NH; (g)+ HCl(g) → NHACI(S) Given the following table of thermodynamic data, Substance AHF (kJ/mol) S /mol.K) NH3 (8) -46.19 1925 HCI (8) -9230 186.69 NH4Cl (s) -3144 946 a. Determine the temperature (in °C) which the reaction is spontaneous Circle one Greater than Less than All None Temp: * Reaction is (non)spontaneous at all temperatures b. Calculate the K for this reaction at 100°C. Answer:
7 Consider the following reaction at 298 K: NH3(g) +HCI(g)NH4CI(s) Using the thermochemical data at 298 K given below (a) Determine the AH for the reaction. (2 marks) (b) Determine the AG for the reaction and comment on its value. (3 marks) (c) Determine the maximum work done available in the reaction. (3 marks) An equilibrium mixture, consisting of 0.5 atm of NHy(), 0.5 atm of HCKg) and excessive of NH Cl(s), is enclosed in a container at 298 K...