Question

step by step for both please

T71 pts Consider the reaction: NH, (g) + HCI (9) ► NH,CI (s) Given the following table of thermodynamic data at 298 ok: Substance by admons Imoly NH HCI NHCI 4 6.19 -92.30 -314.4 192.5 186,69 94.6 The value of K for the reaction at 25°C is 150 1.4 x 10 1.1 x10-16 9.3 x1095 8.4 x109 Question 2 1/1 pts The equilibrium constant for the following reaction is 5.0 x 10% at 25°C. N, (g) + 3H2(g) → 2NH, (9) The value of AGº for this reaction is kJ/mol. -25

Answer 1

∆G =∆H - T∆S

∆G = -RTlnK

# NH3 + HCO N Hyclo DH - E. Al products All reactants - AH Why ca atung AHAL Man = - 314.4 +46.19 + 92.30 - 17591 kilmol Sex as hy e os e Asace = 94,6 - 192,5 - 186.69 = -284,59 Ikmol - 2 AG = AH-TOS = -175,91 x 103 +298 x 284.59 -91.102 kJ/mol AG = - RT enk 91102 Ilmol = 8.314 7/kmol x 298 xink enk = 36.77 K = €136.77 k = 9,3% 1015 :

Cc = 5.0 x 108 T= 25°C = 298 k AG = - RT Ink = - 8,314 J x 298k en 5.0x108 Kimo - 49.686 kJ/mol ~ - 50 kJ/mol