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An analytical chemist is titrating 218.4 ml of a 0.9900 M solution of butanoic acid (HC, H,CO,) with a 1.200 M solution of KO
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Firstly moles of acid and its conjugate base are cake then using the simple equation of Henderson Hasselbalch equation, pH is calculated.

The answer is given in the image,

CKO1 200 M Pha 4.82 Moles of HA B-9900x 218.4 1o00 0.21622mo, Molesqkouadded 1.200x7.48 iooo 0.093336mol Moles HA mauned 0.2

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