Answer is enthalpy of solid barium hydroxide plus water is greater than that of the solution, at the same temperature.
Ba(OH)2(s) + H2O(l) -> Ba(OH)2(aq)
Here, ∆H = ∆fH(Ba(OH)2(aq)) - [∆fH(Ba(OH)2(s) + ∆fH(H2O)]
Since, ∆H is negative hence subtracted term is greater than that of term from which it is selected.
The dissolution of barium hydroxide in water is an exothermic process, which statement is correct? O...
The dissolution of barlum hydroxide in water is an exothermic process. Which statement is correct? The enthalpy of solid barium hydroxide plus pure water is less than that of the solution, at the same temperature. The enthalpy of solid barium hydroxide plus pure water is greater than that of the solution, at the same temperature. O The enthalpy of solid barium hydroxide plus pure water is the same as that of the solution, at the same temperature. O The temperature...
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3. Barium hydroxide Ba(OH)2 was dissolved in pure water at 5 Cuntil a saturated solution was obtained. The pH of this solution was found to be 12.25. a) (2 marks) What is the molar solubility of Ba(OH), in pure water at this temperature? Express your answer in mol/L. Show your work. b) (1 mark) What is the Kp of Ba(OH)2 at this temperature? Show your work. c) (0.5 marks) If Ba(OH)2 was added to a solution already containing 0.100 M...