Question

As a parallel-plate capacitor with circular plates 22 cm in diameter is being charged, the current density of the displacement current in the region between the plates is uniform and has a magnitude of 16 A/m2. (a) Calculate the magnitude B of the magnetic field at a distance r = 45 mm from the axis of symmetry of this region. (b) Calculate dE/dt in this region.

Answer 1

@ Given, diameter of circular plates in radius of circulasplate, R = diameter - 22 cm = llam and displacement current density, Id = 16 A/mm we have displacement current for uniform Ja ide o X R = 16 x 1 * (10) A ( = 0.607904 A From Ampere's law, Bids = Mo i enclosed e is a circular loop, radius r Centered on the axis of capacitor. By Symmetry the B field is Constant in magnitude on this loop Such as

B (258) = M'enclosed & Mold in Bu Hold ter 2018 ITF Iyy 0 200 4 H 2 Here, r= 45mm = 0.045 m be the distance from the axis of symmetsy of this region B . 417 X10 x 16 x 0-045 B = 45216 x 10-77 Again, displacement current E (TR) La 2 T, XOR) = € (IRO de 6

8.854 x 10-12 M. Second : ha 1. 80709 x 10" second
Thanks you.