The circular plates of a parallel-plate capacitor are 6.00 cm in diameter and are spaced 5.00...
A parallel-plate capacitor is constructed of two horizontal 12.8-cm-diameter circular plates. A 1.4 g plastic bead with, a charge of -6.4 nC is suspended between the two plates by the force of the electric field between them. Which plate, the upper or the lower, is positively charged? What is the charge on the positive plate?
Two circular disks spaced 0.50 mm apart form a parallel-plate capacitor. Transferring 1.70 ×10 electrons from one disk to the other causes the electric field strength to be 4.00 ×10^5N/C What are the diameters of the disks?
Two 2.30 cm × 2.30 cm plates that form a parallel-plate capacitor are charged to ± 0.708 nC . A.)What is the electric field strength inside the capacitor if the spacing between the plates is 1.40 mm ? B.)What is potential difference across the capacitor if the spacing between the plates is 1.40 mm ? C.)What is the electric field strength inside the capacitor if the spacing between the plates is 2.80 mm ? D.)What is the potential difference across...
A parallel-plate capacitor is formed from two circular electrodes of diameter 5.5 cm spaced 1.5 mm apart. The electric field strength inside the capacitor is 2.0 × 106 N/ C. Part A What is the charge (in nC) on each electrode? Express your answer using two significant figures. Q5352 nC Submit reviouS Answers Req uest Answer X Incorrect; Try Again; 4 attempts remaining
Two 2.0 cm ✕ 2.0 cm plates that form a parallel-plate capacitor are charged to 0.773 nC. Calculate (i) the electric field strength inside and (ii) the potential difference across the capacitor if the spacing between the plates is (a) 1.2 mm and (b) 2.4 mm. (i) (N/C) (ii) (V) (a) (b)
A parallel-plate air capacitor is made by using two square plates, 13 cm × 13 cm each, spaced 3.7 mm apart. It is connected to a 10-V battery. If the capacitor remains connected to the battery and the plates are pulled apart to a separation of 7.7 mm . a) What is the new capacitance? b) What is the new charge on each plate? c)What is the new electric field between the plates? d) What is the new energy stored...
A parallel plate capacitor is constructed with circular plates of radius 0.750 cm and plate separation 0.0500 mm. If the capacitor is connected across a 37.2 V source, find: a) the capacitance b) the surface charge on each plate c) The energy stored in the capacitor d) the electric field between the plates e) the energy density between the plates
As a parallel-plate capacitor with circular plates 22 cm in diameter is being charged, the current density of the displacement current in the region between the plates is uniform and has a magnitude of 16 A/m2. (a) Calculate the magnitude B of the magnetic field at a distance r = 45 mm from the axis of symmetry of this region. (b) Calculate dE/dt in this region.
As a parallel-plate capacitor with circular plates 27 cm in diameter is being charged, the current density of the displacement current in the region between the plates is uniform and has a magnitude of 23 A/m2. (a) Calculate the magnitude B of the magnetic field at a distance r = 80 mm from the axis of symmetry of this region. (b) Calculate dE/dt in this region.
A parallel-plate capacitor is constructed with circular plates of radius 0.056 m. The plates are separated by a distance of 0.25 mm, and the space between the plates is filled with a dielectric with dielectric constant κ. When the capacitor is charged to 1.2 µC, the potential difference between the plates is 750 V. What is the value of κ?