Homework Answers
given
R and R ' = 2.17 R
D = 2.11 R
Q = 3.07 x 10-6 C
when the net electric field is zero at point P
so E = ( k Q D / ( D2 + R2 )3/2 ) + ( k Q' D / ( D2 + (2.17R)2 )3/2 ) = 0
Q / ( D2 + R2 )3/2 ) = - Q' / ( D2 + (2.17R)2 )3/2 )
Q ' = - Q ( (2.11R)2 + (2.17R)2)3/2 / ( (2.11R)2 + R2 )3/2
= - Q ( 4.452 + 4.7089 )3/2 / ( 4.452 + 1 )3/2
= - Q x 2.178
Q ' = - 3.07 x 10-6 x 2.178
Q ' = - 6.6866 x 10-6 C
the uniformly distributed charge on the larger ring if the electric field is zero is Q ' = - 6.6866 x 10-6 C
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