Here we apply formula for electric potential of ring on its axis and electric potential of point charge.
The integral represents the sum of the charges of all the infinitesimal pieces, and this sum...
These are all the answers I have tried that are wrong. Review Part A A ring with radius R and a uniformly distributed total charge Qlies in the xy plane, centered at the origin. (Figure 1) What is the potential V(z) due to the ring on the z axis as a function of z? Express your answer in terms of Q, z, R, and eo or Figure 1 of 1 ATEO View Available Hint(s) 0 r.1on Submitted Answers ANSWER 1:...
8. (3) A ring with charge Q and radius R is in the x-y plane and is centered on the origin. Derive an expression for the electric potential at a point P on the z-axis a distance z above the x-y plane Please also indicate how much energy it would take to bring a charge q from far away and place it at point P
The electric field on the axis of a ring of charge near its center( which is located at z=0) is given by E(z)= ((kQ)/(R^3)) z. The ring has a radius R=5 and total charge of Q= 1 uC 1. A charged particle (m = 1 mg, q = –1 nC) is placed near the center of the ring. Write down and expression for the force F(z) that acts on the particle, in terms of kC, Q, q, R and z....
Please show all work! A Two parallel rings, each of radius R, are separated by a distance R. A positive charge^+Q is uniformly distributed around the upper ring and a negative charge^-Q is uniformly distributed around the lower ring. Let z be the vertical coordinate, with z = 0 taken to be the center of the lower negatively charged ring. What is the direction and magnitude of the electric field at the point A on the vertical axis, a distance...
A thin nonconducting rod with a uniform distribution of positive charge Q is bent into a circle of radius R (see the figure). The central perpendicular axis through the ring is a z axis, with the origin at the center of the ring. What is the magnitude of the electric field due to the rod at (a) z = 0 and (b) z = ∞? (c) In terms of R, at what positive value of z is that magnitude maximum?...
For the next six problems, consider a uniformly charged disk of radius R. The total charge on the disk is Q. To find the electric potential and field at a point P (x>0) on the x-axis which is perpendicular to the disk with the origin at the center of the disk, it is necessary to consider the contribution from an infinitesimally thin ring of radius a and width da on the disk, as shown. What is the surface charge density...
2. Figure shows a ring of radius R 4m and a point particle located at the center of the ring. Point P is on the central z axis, at distance z 3 m above the ring. The ring is charged with the uniform linear charge density of 1 10 C/m. What is the charge of the point particle, Q, if the net electrical field at point P is zero? -3 m R-4 m
A thin nonconducting rod with a uniform distribution of positive charge Q is bent into a circle of radius R (see the figure). The central perpendicular axis through the ring is a z axis, with the origin at the center of the ring, what is the magnitude of the electric field due to the rod at (a) z = 0 and (b)2 = oo? (c) In terms of R, at what positive value of z is that magnitude maximum? (d)...
24. A thin nonconducting rod with a uniform distribution of positive charge Q is bent into a complete circle of radius R (Fig. 22-48). The central perpendicular axis through the ring is a z axis, with the 0 and (b)z-oo? (c) In terms of R, at what positive value of z is that magnitude maximum? (d) If origin at the center of the ring. What is the magnitude of the electric field due to the rod at (a) z R-...
Find an expression for the position y (along the positive axis perpendicular to the ring and passing through its center) where the electric field due to a charged ring is a maximum. Also find an expression for the electric field at that point. (Use the following as necessary: R for the radius of the ring, Q for the charge on the ring and k for Coulomb's constant. Enter the magnitudes. Assume Q is positive.) y = E =