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Plz explain why and how the answer was derived



















QUESTION 18 Section 18.9 Gauss Law 20. A cubical Gaussian surface surrounds two charges, J1 = +6.0 × 10-12 C and q.--2.0 × 10-12 C, as the draw- ing shows. What is the electric flux passing through the surface? QUESTION 20
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Answer #1

Solution:

The cubical surface is a Gaussian surface. It is a closed surface and charges are enclosed by the surface. There are two charges inside. One is positive and other is negative. So the net charge enclosed will be their sum.

For solving the question we can use Gauss's law. According to this law, the total electric flux out of a closed surface is equal to the charge enclosed divided by the permittivity.

ANSWER: 0.4519 Vm

Calculations are given below:

Crcusss law: ctơíc G enclesec Hene total chanae enclosed -12 -12 -12 12. Flux φ 12 g,85%16 Nole: in the enclosed chun

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