Solution:
The cubical surface is a Gaussian surface. It is a closed surface and charges are enclosed by the surface. There are two charges inside. One is positive and other is negative. So the net charge enclosed will be their sum.
For solving the question we can use Gauss's law. According to this law, the total electric flux out of a closed surface is equal to the charge enclosed divided by the permittivity.
ANSWER: 0.4519 Vm
Calculations are given below:
Plz explain why and how the answer was derived QUESTION 18 Section 18.9 Gauss' Law 20....
s. Section 18.9 Gauss' Law 54. A spherical surface completely surrounds a collection of charges. d the electric flux through the surface if the collection consists of (a) a single +3.5 x 10-6 C charge, (b) a single -2.3 x 10-6 C charge nd e and (c) both of the charges in (a) and (b).
A cubical Gaussian surface surrounds two charges, q,-+6.4 x 10-12 C and q2--2.0 × 10-12 C, as the drawing shows. What is the electric flux passing through the surface?
A cubical Gaussian surface surrounds three positive charges,
each has a charge q11 = +4.00 × 10-12
C, and two negative charges, each has a charge q22 = −2.60
× 10-12 C as the drawing shows. What is
the electric flux passing through the surface?(The permittivity of
free space ε00 = 8.85×10-12C²/(N.m²))
A cubical Gaussian surface surrounds one positive charge that has a charge q_1 = +8.00 times 10^-12 C, and four negative charges, each has a charge q_2 = -2.00 times 10^-12C as the drawing shows. What is the electric flux passing through the surface?(The permittivity of free space epsilon_0 = 8.85 times 10^-12 C^2/(N.m^2))
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