Question

Version B Tests 6. An object attached with a spring undergoes simple ha displacement x = (1.2m) Cos (1.51 C). Compare with the su harmonic equation: x-Acos (w t). spring undergoes simple harmonic motion, represented by the cos (1.5 t). Compare with the standard equation for simple (1) Find the amplitude of oscillation? (ii) Calculate the displacement x at r = 0, 1, date the displacement x at i=0, 1.2.3.4 and 5 seconds and filled the table below Time Displacement t(s) x (m) (iii) Draw the displacement - time graph of the oscillatory motion on the following graph. x (m) of - 5 t(s)

Answer 1

a=(1:2M) Cos () a= A cos (wt) amplitude l A = 1.2m (i 2 = 1-265 (t's Tit) x(0) = 1.2 oso = 1.2 [: Coso = 1) x ) = 1.2.CoS (157) = 1.2.(3T) = 0. [653] =0 J x (2) = 1.2cos (37) - 1.2x-1 = -1.2 , [cos 3T1 =-1] x(3) = 1.2os (4.57) = 1. 25 (T) = 0 x (4) = 1.2 Cos (67) = 1.2x - 1.2 & (5) - 1.2 cos (9.5T) = 0 alt) 7.2 - -