Br in Br- has oxidation state of -1
Br in BrO3- has oxidation state of +5
So, Br in Br- is oxidised to BrO3-
Al in Al+3 has oxidation state of +3
Al in Al has oxidation state of 0
So, Al in Al+3 is reduced to Al
Reduction half cell:
Al+3 + 3e- --> Al
Oxidation half cell:
Br- --> BrO3- + 6e-
Balance number of electrons to be same in both half reactions
Reduction half cell:
2 Al+3 + 6e- --> 2 Al
Oxidation half cell:
Br- --> BrO3- + 6e-
Lets combine both the reactions.
2 Al+3 + Br- --> 2 Al + BrO3-
Balance Oxygen by adding water
2 Al+3 + Br- + 3 H2O --> 2 Al + BrO3-
Balance Hydrogen by adding H+
2 Al+3 + Br- + 3 H2O --> 2 Al + BrO3- + 6 H+
This is balanced chemical equation in acidic medium
Sum of coefficients = 2 + 1 + 3 + 2 + 1 + 6
= 15
Answer: 15
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