What Volume (in mL) of KBr solution must be taken so it will contain 2.83x10^-5 moles of KBr? KBr solution is made by dissolving 0.42 grams of KBr in enough water to yield 17 mL of solution.
Mass of KBr = 0.42 gm
Molar mass of KBr = 119.002 g/mol
Moles of KBr = 0.42 g / 119.002 g/ mol = 0.003529 Moles
Volume of water to be added = 0.003529 x 1000 / 2.83 x 10-5 = 124712 ml or 124.7 Liter
Hence if we want to make 2.83 x 10-5 M solution using 0.42 gm of KBr then we have use 124.7 Liter of water to make up.
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