A tablet containing calcium carbonate and fillers with a mass of 1.631 g was dissolved in...
A tablet containing calcium carbonate and fillers with a mass of 1.631 g was dissolved in HCl. After the fillers were filtered out, the HCl was neutralized by adding sodium carbonate. The resulting precipitate was pure calcium carbonate (with the fillers removed). The solid calcium carbonate was collected on a watch glass that had a mass of 46.719 g when empty. After the calcium carbonate had been allowed to dry, the mass of the watch glass plus product was found...
A tablet containing calcium carbonate and fillers with a mass of 1.631 g was dissolved in HCl. After the fillers were filtered out, the HCl was neutralized by adding sodium carbonate. The resulting precipitate was pure calcium carbonate (with the fillers removed). The solid calcium carbonate was collected on a watch glass that had a mass of 46.719 g when empty. After the calcium carbonate had been allowed to dry, the mass of the watch glass plus product was found...
The active component in one type of calcium dietary supplement is calcium carbonate. A 1.2450-g tablet of the supplement is added to 50.00 mL of 0.5000 M HCl (aq) and allowed to react. After completion of the reaction, the excess HCl (aq) requires 40.65 mL of 0.2535 M NaOH (aq) for its titration to the equivalence point. What is the calcium content of the tablet, expressed in milligrams of Ca^2+? m_ca^2+ = mg
A tablet weighing 2.074 g and containing aluminium salts was dissolved and diluted to 100.0 mL in a volumetric flask. A 25.00 mL aliquot was removed and treated with enough ammonia to precipitate the aluminium (Al) present as aluminium hydroxide (Al(OH)3). After ignition at 800 oC, this precipitate was converted to aluminium oxide (Al2O3) weighed 0.1967 g. Calculate the Al% in the tablet.
PART A: REACTION STOICHIOMETRY Thal 2 Tablet 1 Tablet 2 Average Data 2020 199 g Mass of NaHCO, Mass of Beaker + Acetic Acid + NaHCO3+ Watch Glass before Reaction Mass of Beaker + Reaction Mixture + Watch Glass after Reaction Calculated Results (see below for guidance) III 194.919|187.31 g Mass of CO2 Gas Released 2 3240 mol 0.98 - Moles of CO2 Gas Released .062 Moles of CO2, Corrected for Amount Dissolved* (see below for note) Moles of NaHCO3...
PART B: ANALYSIS OF AN ANTACID Tablet 1 Tablet 2 Data 0 Mass of Beaker + Acetic Acid + Tablet + Watch Glass before Reaction Mass of Beaker + Reaction Mixture + Watch Glass after Reaction Calculated Results 195, 14 186, 60g 194.33 g 1 185.71g 0.81 g CO2 0.0184 mole 0.0224 mol or 0.327 Mass of CO, Gas Released Moles of CO2 Gas Released Moles of CO2, Corrected for Amount Dissolved" (see note below) Moles of NaHCO3** (see note...
A 18.5 g sample of a mixture of magnesium carbonate and calcium carbonate is treated with excess HCl. The resulting reaction produces 5.23 L of carbon dioxide gas at 28 °C and 753 torr. Write a balanced chemical equation for the reaction that takes place between magnesium carbonate and HCl. Include physical states. chemical reaction: Write a balanced chemical equation for the reaction that takes place between calcium carbonate and HCl. Include physical states. chemical reaction: Calculate the total number...
A Tums tablet weighed 1.319 g. Using the procedure of this experiment, the tablet was dissolved in, and reacted with, an excess amount of HCl (125.00 mL of 0.101 M HCl). The excess unreacted HCl was titrated with NaOH; 18.75 mL of 0.101 M NaOH was used to reach the endpoint. Calculate the moles of HCl that did not react with the antacid. Calculate the moles of HCl that did react with the antacid. Calculate the mass of HCl that...
5. A 2.600 g sample of limestone was dissolved in excess 0.200 M HCl(aą): CaCO(s) 2 HCa)Ca (a2 CT(a)CO (g)HO) Excess 0.10 M (NH C20(a) was added to the resulting solution to precipitate the calcium ions as calcium oxalate, CaC204(s). Ca (aq) (NH).CO(a)CaC,04(s)2 NH (aq) The precipitate was filtered and dried three times to a constant mass of I 036 g. Determine the mass% Ca in the limestone sample.
1. A particular brand of antacid contains 500 mg of CaCO3 per 2.0 g tablet according to the label. How many mol of CaCO3 are contained in one tablet? nCaCO3 = ___ mol Ans. 0.005mol 2. The reaction by which the antacid neutralizes HCl is 2 HCl(aq) + CaCO3(s) à CaCl2(aq) + CO2(g) + H2O(l) How many moles of HCl can be neutralized by one tablet? nHCl = 0.010 mol 3. 50.0 mL of 0.300 M HCl are used to...