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t1/2 means that the voltage (or charge) of the system will increase to half more of...

t1/2 means that the voltage (or charge) of the system will increase to half more of what is left in a time equal to t1/2 seconds. Therefore if a system is already at half charge (t1/2 seconds after starting) then after t1/2 more seconds the system will be charged to 50% plus half of 50%. That is 25% more, or 75% of the entire charge. Let's say that four t1/2's have gone by. That means that the charge (or voltage) is at (50% + 1/2*50% + 1/2*1/2*50% + 1/2*1/2*1/2*50%) = 93.75% of maximum charge. Yikes! Now look in your manual for a more simple mathematical derivation of this concept.

Given t1/2 to be 0.7915 seconds, how long should it take to reach 75% of maximum charge? answer in seconds. (Answer with three significant figures or N/A if there is no answer.)

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FYOM TLO12) ti12 Time Constant is tip Ln/2) O-7915 Ln(2) T:11419 5 In a Rc CiYcult Cha Yae as a function for Chorging 1s time

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