Question

2. You have been hired as a physics consultant by the special effects team in charge of the new Mad Max movie. George Miller is famous for doing a lot of practical effects, which essentially means a real person doing something real crazy like flipping a semi truck over at 50 mph. The effects team wants you to work out the physics of a particular stunt where a War Boy is launched vertically into the air from a spring loaded platform at the exact moment Max jumps off a cliff directly above. The director has three ideas for the scene: (1) the two stuntmen crash into each other just as the War Boy reaches the highest point in his trajectory, (2) they meet just before the War Boy hits the ground, or (3) they meet at some random point in the air. Let's model the system as the War Boy starting from y 0 with speed v, and the Max starting from a height h (directly above) falling from rest. A. Find a general expression for the height above the ground that the stuntmen collide? Your answer will be an algebraic expression written in terms of h, v, and g. [5 pts] B. How high of a cliff does Max have to be on, i.e. what is the maximum value of h, such that the stuntmen collide right before the War Boy hits the ground? [5pts] C. How high of a cliff does Max have to be on if George instead wants the collision to occur at the instant when the War Boy is at his highest point above the ground? [5pts]

Answer 1

ANSWER;

--8--- 2 PART-EN) let has height 'H' both collide distance travelled by war boy - dw=H distance travelled by maximum dm = h-H NOW - H= vit - gt ² 0 and for max , 5) K-H Z viloa. h-H = 0+įgt?) By ① and ① H = vilt) – h+H

NOW h-H = 19 x 4 Ривт - 3 taken by war boy Time to come down Time taken by stunt man to come down T = 127 SO1 squaring on both side con sea City

PART-O Time taken by war boy to reach height man T= distance travelled by max í this time Id = 0+2gT² | man height of har boy Hi = 4y SD h = Hitd بال