1. Find the following z values for the standard normal variable Z. (You may find it useful to reference the z table. Negative values should be indicated by a minus sign. Round your answers to 2 decimal places.)
a.P(Z ≤ z) = 0.8604
b.P(Z > z) = 0.714
c.P(−z ≤ Z ≤ z) = 0.79
d.P(0 ≤ Z ≤ z) = 0.3202
2. An estimated 1.8 million students take on student loans to pay ever-rising tuition and room and board (The New York Times, April 17, 2009). It is also known that the average cumulative debt of recent college graduates is about $22,500. Let the cumulative debt among recent college graduates be normally distributed with a standard deviation of $8,000. Approximately how many recent college graduates have accumulated a student loan of more than $35,000? (You may find it useful to reference the z table. Round "z-value" to 2 decimal places.)
1. Find the following z values for the standard normal variable Z. (You may find it...
Find the following probabilities based on the standard normal variable Z. (You may find it useful to reference the z table. Leave no cells blank - be certain to enter "0" wherever required. Round your answers to 4 decimal places.) a.P(−1.3 ≤ Z ≤ −0.73)b.P(0 ≤ Z ≤ 1.62)c.P(−1.41 ≤ Z ≤ 0.14)d.P(Z > 3.1)
An estimated 1.6 million students take on student loans to pay ever-rising tuition and room and board (The New York Times, April 17, 2009). It is also known that the average cumulative debt of recent college graduates is about $21,700. Let the cumulative debt among recent college graduates be normally distributed with a standard deviation of $9,000. Approximately how many recent college graduates have accumulated a student loan of more than $30,000? (You may find it useful to reference the...
Find the following z values for the standard normal variable Z. (You may find it useful to reference the z table. Negative values should be indicated by a minus sign. Round your answers to 3 decimal places.) a. P(Z <z) = 0.1441 b. P(ZSZ < 0) = 0.1775 c. P(Z > Z) = 0.7344 d. P(0.3 SZ sz) = 0.3111
Find the following z values for the standard normal variable Z. (You may find it useful to reference the z table. Negative values should be indicated by a minus sign. Round your answers to 3 decimal places.) a PIZS z) = 0.1176 b. P(Z SZ50) = 0.1579 c. P(Z > z) = 0.9764 d. P(0.39 SZ sz) = 0.3253
Find the following z values for the standard normal variable Z. (You may find it useful to reference the z table. Negative values should be Indicated by a minus sign. Round your answers to 2 decimal places.) a. PZSz) 0.9474 b. P(Z>z) 0.7103 d. |Plo szsz) = 0.2507
Find the following z values for the standard normal variable Z. (You may find it useful to reference the z table. Negative values should be indicated by a minus sign. Round your answers to 3 decimal places.) a. P(Z ≤ z) = 0.1065 b. P(z ≤ Z ≤ 0) = 0.1746 c. P(Z > z ) = 0.9412 d. P(0.4 ≤ Z ≤ z) = 0.3177
The typical college student graduates with $27,100 in debt (The Boston Globe, May 27, 2012). Let debt among recent college graduates be normally distributed with a standard deviation of $5,000. [You may find it useful to reference the z table.] a. What is the probability that the average debt of two recent college graduates is more than $27,000? (Round “z” value to 2 decimal places, and final answer to 4 decimal places.) b. What is the probability that the average...
Find the following z values for the standard normal variable Z. (You may find it useful to reference the z table. Negative values should be indicated by a minus sign. Round your answers to3 decimal places.) a. P(Z s z)-0.1020 b. P(z s Z s 0)-0.1772 c. P(Z> z) 0.9929 d. P(0.40 sZsz)- 0.3368
Find the following z values for the standard normal variable Z. (You may find it useful to reference the z table. Negative values should be indicated by a minus sign. Round your answers to 2 decimal places.) a. P(Z s z) 0.9474 b. P(Z> z)-0.7103 с. d. P(OsZsz) 0.2507
Find the following z values for the standard normal variable Z. (You may find it useful to reference the z table. Negative values should be indicated by a minus sign. Round your answers to 3 decimal places.) a. P(Z S z) 0.1020 b. P(z s Zs0) 0.1772 c. P(Z> z)-0.9929 d. P(0.40 sZz)0.3368 1.270 2.450