Question

Problem 3.38 (Multistep) A proton is located at <0, 0 1.5 x 10 9> m and an alpha particle consisting of two protons and two neutrons is located at 3.6 x 10 9 0 1.0 × 10 9>. Express your answers in vector form. Part 1 Your answer is partially correct. Try again (a) Calculate the force the proton exerts on the alpha particle. 1.847e-10 1.2827e-10 By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instructor Attempts: 2 of 10 used SAVE FOR LATERSUBA Earn Maximum Points available only if you answer this question correctly in three attempts or less. Part 2 Your answer is partially correct. Try again. (b) Calculate the force the alpha particle exerts on the proton 2.25e8 156250000 >N

Answer 1

a)

Force proton exerts on alpha particle is given by

$\overrightarrow{F}=\frac{Kq_{1}q_{2}}{r^{2}}\widehat{r}$

$\overrightarrow{r}=<3.6\times 10^{-9},0,1\times 10^{-9}>-<0,0,-1.5\times 10^{-9}>=<3.6\times 10^{-9},0,2.5\times 10^{-9}>$

$\overrightarrow{F_{P\alpha }}=\frac{(9\times 10^{-9})(2\times 1.6\times 10^{-19})(1.6\times 10^{-19})}{(\sqrt{(3.6\times 10^{-9})^{2}&plus;(2.5\times 10^{-9})^{2}})^{2}}\times \frac{<3.6\times 10^{-9},0,2.5\times 10^{-9}>}{\sqrt{(3.6\times 10^{-9})^{2}&plus;(2.5\times 10^{-9})^{2}}}$

$\overrightarrow{F_{P\alpha }}=<1.97\times 10^{-11},0,1.368\times 10^{-11}>N$

b)

Force on alpha particle exerted by proton is

$\overrightarrow{F_{\alpha p}}=-\overrightarrow{F_{P\alpha }}=<-1.97\times 10^{-11},0,-1.368\times 10^{-11}>N$