A charge of 2.15 mC is placed at each corner of a square 0.240 m on a side.
Part A
Determine the magnitude of the force on each charge.
Express your answer to three significant figures and include the appropriate units.
PLEASE DRAW OUT AND FULLY EXPLAIN YOUR STEPS AND ANSWERS. i keep getting my answers wrong and I cant figure out where I am messing up. I WILL RATE AND COMMENT!!!!!
THANKS
force due to adjacent charge
F1 = F3 = k q1 q / a^2 = 9*10^9* (2.15*10^-3)^2 / 0.24^2
F1 = F3 = 7.22*10^5 N
resultant force of F1andF3
F13^2 = F1^2 + F3^2
F13 = 10.21*10^5 N
force due to corner charge
F2 = k q^2 / ( 2 a^2)
F2= 9*10^9*( 2.15*10^-3)^2 / ( 2* 0.24^2)
F2 = 3.61*10^5 N
net force on any charge,
F = F13 + F2
F = ( 10.21 + 3.61) *10^5
F = 13.82*10^5 N
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