Question

The behaviors of four different solutes when dissolved in water are indicated by the four equations below. Match each of the resulting solutions to its expected behavior in a conductance apparatus like the one shown to the left, if the solute is present at a concentration of 0.2 М. Battery Cathode (negative electrode) Anode positive electrode) HNO2(aq) H2O(l) H30* (aq) NO2- (aq) Would produce a dim light. HNO3()H2O(l) -H3O* (aq) +NO3 (aq) Would not cause the bulb to light. На0 Ba (ОН)2 (s) Вa+ (аq) + 20н (аq) Would produce a bright light. Нао Would not cause the bulb to light. C12 H22 11(s) C12H22011(aq) Submit Answer Retry Entire Group 6 more group attempts remaining Previous Next

Chemistry help

Answer 1

Flow of electron tmout the circuit produces electricity, and which makes the buth that is the cause of bulb to light. D) In reaction HNO 292.+.14(e) = Hot (@ad + N5600 . Sina, the reaction is in equilinium, so that the electricity passing throub itb;E=0: 1 the It will not cause the bulb to light 2) thg 60 +40 (0"> Hot@g) + NO 690, one election is inished in this reaction. So only one election Pristiny i so'lt produce a dim light 3) Ba@u209) Hey Ban tegd + 2016 Since two elections are involved in this reaction, it would pro- duce a brisht lint Bites : 2 015 | 4 , , , , , , , , , , , , , , No electrons one inolved in this reaction. So that no ē is passing Through the aruit so that it would not cause the bulb to light. sutus ja toisaalt

L D HNO (aq+ Hole Hotego + Ng Cao Would not calese bulb to light 2) HNG (0) +tho( Hot (60) + No.(ag) → Would produce a dim light a) Bast246) Hobo y Ban Tego + 2oübe} = would produce a bright Light 8 Catfig) the C2 H2 2011 (99) Would hat cause the ball to light + loed -