In order to estimate the population proportion with a high school education, you need a minimum sample size to result in a margin of error of 7%. For a 95% CI, what is that sample size?
Let proportion, p = 0.50
Margin of error, E = 0.07
Confidence Level, CL = 0.95
Significance level, α = 1 - CL = 0.05
Critical value, z = NORM.S.INV(0.05/2) = 1.9600
Sample size, n = (z² * p * (1-p)) / E² = (1.96² * 0.5 * 0.5)/ 0.07²
= 195.9928 = 196
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