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14. A box contains 6 purple balls, 7 yellow balls and 8 green balls. Three balls are selected from the box without replacement (i) Find the probability that the first selected ball is purple, the second selected ball is green and the third selected ball is purple. (ii) Find the probability that the first selected ball is not purple, the second selected ball is yellow and the third selected ball is green.

Here, "without replacement" means that the ball is not put back into box. I want to see the thought process behind this so that I could approach similar problems on my own, so please attempt to show every step and formula used, thank you.

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