Question

• A Virginia-class submarine has a test-depth (peacetime maximum) of {{{CLASSIFIED, but let's assume 490m, same as Seawolf}}}. • How many Pascals of pressure is it under at that depth? 4.9x106 Pa • How many atmospheres of pressure is this? 48.5 atmospheres! • If the sub has a surface area of 4100 m2, how much force is trying to collapse the whole sub? 20 GN • P = Po + pgh • Water = 1000 kg/m3 • 1 atm = 101000 Pa

Answer 1

briven, H=490 m. A Pressure at that depth = ? pat H = 4gom is given by - P = Pot Sw gH : Po: atmospheric pressure p=101000 pat (1000 kg/m3 xq - 81 m/s2 x 490m) IP = 4.9x100 pa Ang Ans ③) How may atm is this P in atm) = pressure at H=49om in pa Patm = 48.5 atmosphesen 101000Pa P = 4.9x10opa (P = 48.5 atm lang P = 48.5 atm © A = 4100m2 ure, Force = pressure X Area F = 4.9x106 N x 4100 m2 F = 2x1010 N and [109 N= IGN) F = 20 GN / Ane