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You have a pattern which has five nodes and four anti-nodes, with the frequency set to 120.0 Hz. The string is 1.15 m long, and the pulley over which it is run is located 1.00 m from the vibrator. The mass of the string is 0.425 grams. What is the wavelength of the wave, in MKS units? The wavelength of the wave is..... [units. But dont enter the units!]
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length of the string = L velocity of wave = v nv frequency of nth harmonic-f- forn-5 2L L=1.15m Im | v=5.520

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