the initial speed of blood cells is , v1 = v
the final speed of blood cells is , v2 = 0
initial distance = very far off (infinity)
final speed = 2*radius = 2*(6.40/2)*10-6 = 6.40*10-6 m
The conserving energy is ,
q1*q2/4*pi*o*r + 1/2*m*v2 = constant
(q1*q2/4*pi*o*) + 2*(1/2*m*v2) = q1*q2/4*pi*o*2r + 0
calculate the velocity of the cell ,
m*v2 = q1*q2/4*pi*o*2r
v = sqrt[q1*q2/4*pi*o*2r*m]
v = sqrt[(-2.60*10-12)*(-2.70*10-12)/4*3.14*8.85*10-12*6.40*10-6*6.35*10-14]
v = 394.20 m/s
These are experiences the maximum acceleration when they just barely touch each other .
so,
m*a = q1*q2/4*pi*o*(2r)2
a = q1*q2/4*pi*o*(2r)2*m
a = (-2.60*10-12)*(-2.70*10-12)/4*3.14*8.85*10-12*(6.40*10-6)2*6.35*10-14
a = 2.42*1010 m/s2
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