Question

For the RL circuit shown in Figure P32.17, let the inductance be 3.00 H, the resistance 8.50 , and the battery emf 36.0 V.

Figure P32.17

(a) Calculate the ratio of the potential difference across the resistor to that across the inductor when the current is 2.00 A.
ΔV_R / ΔV_L =
(b) Calculate the voltage across the inductor when the current is 4.50 A.

Answer 1

From the given circuit L:3.004 .: 36V T -VR+ R = 8.502 ay binen, E=360 Current in the circuit, 1 = 2A Vallage doop ocross Resistor, VPTR - 2x8.50 E14V Now, By applying KUL in the orwil, -E + V +Up=0 =) VEE-VR +36-17 - J9V. Hence, = =0.895 by Given, E-36V Curs ont across the chequil, 1: 2.5 A vollage drop acsoss Resistor, VR= IR 4.5x8.5 V 38.25V NUD, By applying kve in the circuit Et Up + 4 = 0 = 86-38.25 -2.25 V. Hence the voltage drop ocross the inductor will be -2.25 » pe Inductos ww oct as oclive element in sucond cage.