Question

ON CAPAC Transient RL Circuit Consider the circuit shown in the figure. The resistance of the wire used to make the inductor is negligible compared to the resistors in the circuit. V-140 V, R; -10.Ohms, Ry - 1100 Ohms, and L-200 H RI WWW For this part, assume that switch S has been closed for a long time so that steady currents exist in the circuit. Find (1) the battery current, (2) the current in resistor Ry, and (3) the current through the inductor Enter the battery current here: Enter the current in resistor Rs here: Enter the current through the inductor here: Thes 0/10 Now the switch is opened. Find the initial voltage across the inductor when switch 5 is opened Sub Tries O/10 Give the current in the inductor after a time of 0.020 measured from the instant of pering which S.

Answer 1

The voltage across an inductor in steady state tends to be zero.An Inductor tries to resist changes in current and thus the current remains the same after turning off the switch.
Solusim: Varuv R, Elon Reallon L : 24 At to, co . The cirmer becomes I RI J = 14d. Battery unent, I Ano.) inductor, I = I = 1044 Current Current through through Rp, R = 0 4 CScanned with CamScanner

when switch in opered, inwit becomes R = 11on s and her - Rat/L 4 tio a 50 a 1:44 - R2t/ A1 = love -Rat IL V. IR : 154e after emitch is opened voltage across inductor just v (4:0) = 154 (Aus.) after 0.02s, falt=0.02) Current in the indueth - IIU*0.02), . Oyb6 A. CS$canned with CamScanner