Question

The combustion reaction for octane burning in oxygen is: 2 C8H18 (l) + 25 O2(g) → 16 CO2(g) +18 H2O(g) ∆H = -10869 kJ . Suppose an oxygen bomb calorimeter is loaded with oxygen gas and excess octane. The oxygen gas has a volume of 480.0 mL, pressure of 5.67 atm, and an initial temperature of 22.1 °C. The calorimeter has a heat capacity of 1.75 kJ/ °C . Assuming the oxygen reacts completely, what is the final temperature of the calorimeter?

Answer 1

dus) Concept heat reelese by Ron = heat gain to raise the tempo Stef 1 find moles of O2 we knave, PV = nRT T = 22.1 + 273.15 5.67 atm x 0.48L T = 295.25k = nxo.0821 alm L x 295.25k n= 5.67X0:48 0.0821 X 295.25 malk N= 0oll 2 mal Step , find heat Relesed by Ron, 2Cg Higll) +25 02(8) 16 (02(8) +18 42008) 25 mole on give = 108 69 X 1035 heat. so. I mole Og give = 10869 4103 - 25 So, 0.112 mol O2 give = 1086941080.112 J 25 = 4881.36 JXl0 = 4.88 KJ X10 2 48.8kJ

haaaaaa2222 Stehl find férial temperature of Colorimeter Heat - k75 heat cafecity. At Heat = 4688KF 48.8 kJ eso. 48.8KJ = 1.75 kJ/c AT DT² 27.89 TE- Ti = 27.89 Te = 27.89 + 2201 TE=49.99 Ten 50°C final tempo = 50°C Thank you, May it help you.