5. For the reaction given below: CH3NH2 + HSO4 = CH3NH3* + SO42- a) The acid...
5. For the reaction given below: CH3NH2 + HSO4 = CH3NH3+ + SO42- a) The acid on the reactant side: b) Its conjugate base (on the product side): 6. a) What is the conjugate base of NH3? b) What is the conjugate acid of HPO42-?
If the acid-base reaction NH2- + HSO4- ⟺ NH3 + SO42- proceeds to the right as written, then we must conclude that Group of answer choices NH2- is a stronger base than SO42-. NH3 is a stronger acid than HSO4-. NH3 is a stronger base than NH2-. NH3 is a weaker acid than NH2-. NH3 is a weaker base than HSO4-.
7. Identify the conjugate acid base pairs in the following chemical equation: CN (aq) + CH3NH3 (aq) a. HCN(aq) CH3NH2 (aq) b. HSO4 (aq) HO (I)SO42(aq) + H20(aq)
Give the conjugate acid for each compound below. Base HSO4- HPO42- NH3
Consider the acid base reaction below and choose the acid and conjugate base from the list. CH3NH2(aq) + H2O(e) = CH3NH3(aq) + OH(aq) A. ه acid conjugate base CH3NH2 CH3NH3 CH3NH2 OH- H20 H20 CH3NH3 None of the above. OH- د ن نیا
The compound CH3NH2 reacts with water to form CH3NH3+ and OH-. On this reaction CH3NH2 acs as a(n) ____. (a) acid (b) base (c) salt (d) catalyst (e) solvent
Question 9 5 pts Consider the following chemical reaction between HSO4 (aq) and H2O(). HSO4 (aq) + H2O(1=5042-(aq) + H3O+ (aq) Select ALL statements that are true regarding the reaction above. SO42-(aq) is the conjugate base of HSO4 (aq). HSO4"(aq) is a base in this reaction. H30*(aq) is the conjugate acid of H20(1). 5 pts Question 10 ... in haated from 200 K to 400K, (see the
In the following equation, label the Bronsted-Lowry acid, base and conjugate pairs. CH3NH2 (aq) + H2PO4- (aq) ↔ CH3NH3+ (aq) + HPO42- (aq)
H₂N 6. (4 pts) Identify which reactant is the acid and which is the base in each reaction below. a. NH3 + HF → NH4+ + F- B H b. HSO4 + HCO3 + H2CO3 + SO42 ft в the acid. 7. (4 pts) Complete the acid/base reactions below. The first reactant given is a. H2PO4 + C0:2 → P04 +, b. HNO3 + H2O - N02"+ H, 0