Solution)
A)
We know, image distance i=d-p
And, i/p=1/2
Where, p= object distance and d= object image separation=39.2 cm
So, p/2 =d-p
D=3p/2
So, p= 2d/3 =2*39.2/3=26.13 cm (Ans)
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B)
Focal length f= (1/i /+ 1/p)^-1
F= (1/d/3 + 1/2d/3)^-1 =(3/d + 3/2d)^-1 = (9/2d)^-1=(2d/9) = 2*39.2/9 =8.71 cm (Ans)
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Good luck!:)
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