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4) A sample of 0.870 g of an unknown compound containing barium ions (Ba2+) is dissolved...
4) A sample of 0.670 g of an unknown compound containing barium ions (Ba2*) is dissolved in water and treated with...
4) A sample of 0.670 g of an unknown compound containing barium ions (Ba2*) is dissolved in water and treated with an excess of NA2SO4. If the mass of the BaS04 precipitate formed is 0.4105 g, what is the percent by mass of Ba in the original compound?
A sample of 0.7360 g of an unknown compound containing barium ions (Ba2+) is dissolved in...
A sample of 0.7360 g of an unknown compound containing barium ions (Ba2+) is dissolved in water and treated with an excess of Na2CO3. If the mass of the BaCO3 precipitate formed is 0.7578 g, what is the percent by mass of Ba in the original unknown compound?
A 21.524 g paint sample was analyzed for barium (Ba2+, MW = 137.327 g/mole) by an...
A 21.524 g paint sample was analyzed for barium (Ba2+, MW = 137.327 g/mole) by an EDTA back titration: Ba2+(aq) + Y4–(aq) à BaY2–(aq). The sample was dissolved in acid and sufficient water was added to produce a volume of 100 mL. 10.00 mL of this concentrated solution was diluted to a volume of 50.00 mL. 25.00 mL of the diluted solution was treated with 33.95 mL of excess 0.09456 M EDTA. The excess EDTA was titrated to the endpoint...
A 0.649-g sample containing only K_2SO_4 and (NH_4)2SO_4 was dissolved in water and treated with Ba...
A 0.649-g sample containing only K_2SO_4 and (NH_4)2SO_4 was dissolved in water and treated with Ba (NO_3)_2 to precipitate all SO^2-_4 as BaSO_4. Find the weight percent of K_2SO_4 in the sample if 0.977 g of precipitate was formed.
A 1.42 g sample of a pure compound, with formula M_2SO_4, was dissolved in water and...
A 1.42 g sample of a pure compound, with formula M_2SO_4, was dissolved in water and treated with an excess of aqueous barium chloride, resulting in the precipitation of all the sulfate ion as barium sulfate. The precipitate was collected, dried, and found to weigh 2.3.3 g. Determine the atomic mass of M, and identify M.
Metal Sulfate Hydrate lab (12 points) 4) An unknown metal sulfate hydrate (MSO XHO) sample with...
Metal Sulfate Hydrate lab (12 points) 4) An unknown metal sulfate hydrate (MSO XHO) sample with the recorded mass below is dissolved in water, and the sulfate ions from the sample precipitated with Ba2+ ions as BaSO4. A pre-massed filter paper is then used to collect the solid BaSO4. Experimental data was recorded below following same procedure in MSH lab. 0.6939 96.06 g/mol Molar mass of SO42- PARTA Mass of unknown metal sulfate hydrate (MSH) Mass of unknown sample sulfate...
A 1.546g sample containing a mixture of only k2So4 and kno3 was dissolved in water an...
A 1.546g sample containing a mixture of only k2So4 and kno3 was dissolved in water an treated with BaCl2, precipitating the So42- as Baso4(pksp=9.96) the resulting precipitate was isolated and yielded 863.5mg of baso4. What is % in mass of K2So4 and Kno3
Consider a 2.0000 g sample containing MgSO4 (FW 120.366). The sample is dissolved and the sulfate...
Consider a 2.0000 g sample containing MgSO4 (FW 120.366). The sample is dissolved and the sulfate is precipitated as BaSO4 (FW 233.39). If the BaSO4 precipitate weighs 1.4900 g, what is the mass % of MgSO4 in the sample?
A solution contains 0.040 M of Na2SO4 and 0.050 M of NaIO3. Another solution of Ba2+...
A solution contains 0.040 M of Na2SO4 and 0.050 M of NaIO3. Another solution of Ba2+ is added to the first solution.( You must accept that the original solution does not include HSO-4). a) Which of the Baryum salts precipitate firstly? b) Calculate the Ba2+ concentration while the first precipitate is occuring. c) While the more dissolved precipitate is precipitating, what is the concentration of anion which forms the less dissolved Baryum salt ? Ba(IO3) Ksp= 1.57x10-9 BaSO4 Ksp= 1.1x10-10
4. A 0.5255 g sample containing an unknown mass of SnCl2 is dissolved in 50.00 mL...
4. A 0.5255 g sample containing an unknown mass of SnCl2 is dissolved in 50.00 mL of water and titrated with 0.02050 M KMnO4 under mildly acidic conditions. The unbalanced titration reaction is shown below. MnO4 (aq) + Sn²(aq) MnO2(8) + Sn** (aq) a. Use the half-reaction method to balance the titration reaction. (5 pts) b. Given that 32.25 mL of KMnO, was required to reach the endpoint, calculate the percent SnCl2 in the sample. (5 pts)
4) A sample of 0.670 g of an unknown compound containing barium ions (Ba2*) is dissolved in water and treated with an excess of NA2SO4. If the mass of the BaS04 precipitate formed is 0.4105 g, what is the percent by mass of Ba in the original compound?
A 0.649-g sample containing only K_2SO_4 and (NH_4)2SO_4 was dissolved in water and treated with Ba (NO_3)_2 to precipitate all SO^2-_4 as BaSO_4. Find the weight percent of K_2SO_4 in the sample if 0.977 g of precipitate was formed.
A 1.42 g sample of a pure compound, with formula M_2SO_4, was dissolved in water and treated with an excess of aqueous barium chloride, resulting in the precipitation of all the sulfate ion as barium sulfate. The precipitate was collected, dried, and found to weigh 2.3.3 g. Determine the atomic mass of M, and identify M.
Metal Sulfate Hydrate lab (12 points) 4) An unknown metal sulfate hydrate (MSO XHO) sample with the recorded mass below is dissolved in water, and the sulfate ions from the sample precipitated with Ba2+ ions as BaSO4. A pre-massed filter paper is then used to collect the solid BaSO4. Experimental data was recorded below following same procedure in MSH lab. 0.6939 96.06 g/mol Molar mass of SO42- PARTA Mass of unknown metal sulfate hydrate (MSH) Mass of unknown sample sulfate...
4. A 0.5255 g sample containing an unknown mass of SnCl2 is dissolved in 50.00 mL of water and titrated with 0.02050 M KMnO4 under mildly acidic conditions. The unbalanced titration reaction is shown below. MnO4 (aq) + Sn²(aq) MnO2(8) + Sn** (aq) a. Use the half-reaction method to balance the titration reaction. (5 pts) b. Given that 32.25 mL of KMnO, was required to reach the endpoint, calculate the percent SnCl2 in the sample. (5 pts)
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