Question

Solve the following hypothesis test problems (hint: use the t-tables in the document "Formulas and Tables" as the reference guide for computing the critical value) 2.) significance level: 5% Sample size: 32 Model: y-alpha + beta*x Alpha: 23.56 SE(alpha): 11.02 SE(beta): 1.87 Beta: 2.23 a) Test for H0: beta-0 b) Test for H0: beta=3 3.) significance level: 5% Sample size: 32 Model: y alpha+ beta*x Alpha: 23.56 SE(alpha): 11.02 Beta: 2.23 SE(beta): 1.05 a) Test for H0: beta-0 Why are the results for both models different? What is the difference of the model? Why does it play a role?

Answer 1

@ Given that n=32 d=5% y= + Bx v = 23-36 B = 2.23 SEO) = 11:02 SECP):1-87 @ Test for Ho:p=0. Test -statistic t= ß sten-2) - SELB) t = 2023 7-87 t=1-1925 ten-2), 57. = 22-2) al- 5% = +(39) at $k = 1.697. tcal =1-1925. ttab = 1.697 Here tcal attab .. we accept Ho ...(p=0

② Test for Ho : B = 3 Test statistic t= ß-3 SEB 2-23-3 1:57 -0.17 = -0,4118 ttab at 5% = tao at 5% = 1.691 teal ttab Accept Ho: B=3 n=32 2:57 y=x+ßa x=23.56 32923 SEC ) 11-02 SE(B) = 1.05 @ Test for Ho:ß = o. anten-z) Sep = 2.23 105 = 2:1238 teal = 2.1238

(22-23 al 5%. = 1.697, teal > ttab .. we Reject to .: +0 1. The results for both different. models are Because it depends on the data we have But here nda, ß are same But the SE (B) is different in two problems. are different. Results of models