Solve the following hypothesis test problems (hint: use the t-tables in the document “Formulas and Tables” as the reference guide for computing the critical value)
First, let's find out the t-critical value from the t-table at 5% and 1% significance level.
df = n - p - 1 = 102 - 1 - 1 = 100
t-critical value at 5% significance level = +1.984 and
-1.984
t-critical value at 1% significance level = +2.626 and -2.626
a) Ho: beta = 0
t-statistic = Coefficient/SE = 3.67/1.589 = 2.31
As t-statistic = 2.31 > 1.984, we reject the null hypothesis.
b) Ho: beta = 0
t-statistic = Coefficient/SE = 3.67/1.589 = 2.31
As 2.31 < 2.626, we fail to reject the null hypothesis.
The results in both models are different because of the
significance level we are using. In the first model, we are using
5% significance level which means that there is a 5% probability of
rejecting a null hypothesis when it is really true. 5% probability
to make a type - 1 error. In the second model, it is 1% which is
less for Type-1 error.
Solve the following hypothesis test problems (hint: use the t-tables in the document “Formulas and Tables”...
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