Show work including formulas used and tables, must be done by hand.
xi |
-2 |
2 |
4 |
5 |
4 |
6 |
7 |
8 |
11 |
yi |
-4 |
1 |
3 |
1 |
3 |
8 |
10 |
20 |
30 |
.
X | Y | XY | X² | Y² |
-2 | -4 | 8 | 4 | 16 |
2 | 1 | 2 | 4 | 1 |
4 | 3 | 12 | 16 | 9 |
5 | 1 | 5 | 25 | 1 |
4 | 3 | 12 | 16 | 9 |
6 | 8 | 48 | 36 | 64 |
7 | 10 | 70 | 49 | 100 |
8 | 20 | 160 | 64 | 400 |
11 | 30 | 330 | 121 | 900 |
Ʃx = | Ʃy = | Ʃxy = | Ʃx² = | Ʃy² = |
45 | 72 | 647 | 335 | 1500 |
Sample size, n = | 9 |
x̅ = Ʃx/n = 45/9 = | 5 |
y̅ = Ʃy/n = 72/9 = | 8 |
SSxx = Ʃx² - (Ʃx)²/n = 335 - (45)²/9 = | 110 |
SSyy = Ʃy² - (Ʃy)²/n = 1500 - (72)²/9 = | 924 |
SSxy = Ʃxy - (Ʃx)(Ʃy)/n = 647 - (45)(72)/9 = | 287 |
a) Slope, b = SSxy/SSxx = 287/110 = 2.6090909
y-intercept, a = y̅ -b* x̅ = 8 - (2.60909)*5 = -5.0454545
Regression equation :
ŷ = -5.0455 + (2.6091) x
b) Coefficient of determination, r² = (SSxy)²/(SSxx*SSyy) = (287)²/(110*924) = 0.8104
yes it is a good fit.
c) Null and alternative hypothesis:
Ho: β₁ = 0 ; Ha: β₁ ≠ 0
α = 0.05
Slope, b = 2.6091
Sum of Square error, SSE = SSyy -SSxy²/SSxx = 924 - (287)²/110 = 175.190909
Standard error, se = √(SSE/(n-2)) = √(175.19091/(9-2)) = 5.00273
Test statistic:
t = b/(se/√SSxx) = 5.4699
df = n-2 = 7
p-value = T.DIST.2T(ABS(5.4699), 7) = 0.0009
Conclusion:
p-value < α Reject the null hypothesis.
d) SSE = SSyy - SSxy²/SSxx =175.19
SSR = SSxy²/SSxx = 748.8091
F = SSR/(SSE/(n-2)) = 748.8091/(175.1909/7) = 29.9197
e) scatter diagram and estimated regression line in a diagram
Show work including formulas used and tables, must be done by hand. Using the following table...
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