You prepare a buffer solution from 10.0 mL of 0.100 M MOPS (3-morpholinopropane-1-sulfonic acid) and 10.0 mL of 0.084 M NaOH. Next, you add 1.00 mL of 4.05 x 10-6M lidocaine to this mixture.
Denoting lidocaine as L, calculate the fraction of lidocaine present in the form LH+.
Homework Answers
moles of MOPS = 0.1 x 10 / 1000 = 0.001
moles of OH- = 10 x 0.084 / 1000 = 0.00084
MOPS + OH- -----------------------------> Salt + H2O
0.001 0.00084 0 0
1.6 x 10^-4 0 0.00084
pH = pKa + log [salt / acid ]
pH = 7.2 + loh ( 0.00084 / 1.6 x 10^-4)
pH = 7.92
[H+] = 10^-7.92
= 1.20 x 10^-8 M
Ka = Kw / Kb = 10^-14 / 8.7 x 10^-7 = 1.15 x 10^-8
fraction of lidocanine = H+ / H+ + Ka
= 1.20 x 10^-8 / (1.20 x 10^-8) + (1.15 x 10^-8)
= 0.510
fraction of lidocaine = 0.510 ----------------> answer
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