Homework Answers
fraction as LH+ = 0.646
Explanation
concentration MOPS = 0.100 M
volume MOPS = 10.0 mL
moles MOPS = (concentration MOPS) * (volume MOPS)
moles MOPS = (0.100 M) * (10.0 mL)
moles MOPS = 1.00 mmol
moles NaOH = (concentration NaOH) * (volume NaOH)
moles NaOH = (0.075 M) * (10.0 mL)
moles NaOH = 0.75 mmol
moles conjugate base formed = moles NaOH added
moles conjugate base formed = 0.75 mmol
moles MOPS remaining = (initial moles MOPS) - (moles conjugate base formed)
moles MOPS remaining = (1.00 mmol) - (0.75 mmol)
moles MOPS remaining = 0.25 mmol
Ka MOPS = 6.3 x 10-8
pKa = -log(Ka)
pKa = -log(6.3 x 10-8)
pKa = 7.20
According to Henderson - Hasselbalch equation,
pH = pKa + log([conjugate base] / [weak acid])
pH = pKa + log(moles conjugate base formed / moles MOPS remaining)
pH = 7.20 + log(0.75 mmol / 0.25 mmol)
pH = 7.68
pOH = 14 - pH
pOH = 14 - 7.68
pH = 6.32222
Kb lidocaine = 8.7 x 10-7
pKb = -log(Kb)
pKb = -log(8.7 x 10-7)
pKb = 6.06
According to Henderson - Hasselbalch equation,
pOH = pKb + log([conjugate acid] / [weak base])
pOH = pKb + log([LH+] / [L])
6.32222 = 6.06 + log([LH+] / [L])
log([LH+] / [L]) = 6.32222 - 6.06
log([LH+] / [L]) = 0.26
[LH+] / [L] = 100.26
[LH+] / [L] = 1.827
[L] / [LH+] = 1/1.827
[L] / [LH+] = 0.547
Adding 1 to both sides,
([L] + [LH+]) / [LH+] = 1.547
total concentration / [LH+] = 1.547
taking reciprocal,
[LH+] / total concentration = 1/1.547
[LH+] / total concentration = 0.646
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