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Problem 14.35 © 6 of 6 m Review | Constants 1 Periodic Table A piston pushes 20 °C water through a horizontal tube of 0.22 -с

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Answer #1

Flow rate,

Q = (P1 - P2) pi r^4/(8 n L)

105 x 10^-6 = [(101325 - P2) pi x 0.22^4 x 10^-12]/(8 x 10^-3 x 2.8)

Pressure, P2 = 3.19 x 10^8 Pa

Force, F = 3.19 x 10^8 x pi x (0.22 x 10^-2)^2

F = 4.86 x 10^3 N

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