4) Let M is molar mass gaseous hydrocarbon.
Volume (V) = 3 liters
Pressure (P) = 0.950 atm
Temperature (T) = 82°C = 273 + 82 = 355 K
Let n is mole of hydrocarbon.
Gas constant (R) = 0.0821 L atm/mol K
PV = nRT
n = PV/RT = 0.950 * 3 / 0.0821 * 355
n = 0.0978 moles
Mass = moles * molar mass
2.55 = 0.0978 * M
M = 26.08 g/mol
So, the hydrocarbon is C2H2 (ethyne).
Lewis dot structure is:
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