Let us first look at the formula of compound interest.
A= P(1+r/n)^nt
Where A is the future value of the investment/loan, including
interest
P is the principal investment amount (the initial deposit or loan
amount)
r is the annual interest rate (decimal)
n is the number of times that interest is compounded per year
t is the number of years the money is invested or borrowed for.
Now since our question calls for compounding annually, the value of n will be 1.
Let us break this question in two parts: one, before withdrawing the money
Second, after withdrawing the money.
Now putting all the values in the given formula, we have the following illustration :
A = 29535(1+4/100)^9
Now why we have taken t as 9? It is because in the 10th year you are withdrawing 1678, for which you won't get interest in the 10th year. Thus firstly we will compound the interest for 9 years.
Therefore we get A= 42038 (rounding off the decimals)
Now in the 10th year you withdraw 1678. So your remaining balance is 42038 - 1678 = 40360
Now for the remaining 13 years your principle amount is 40360.
Applying the formula once again:
A= 40360(1+4/100)^13
= 67202 (rounding of the decimals)
So you will receive 67202 after 22 years.
Hope your query is solved. Kindly give this answer a thumbs up.
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