Solution)
From gauss law,
We know,
Electric Flux = Qenclosed/Eo
= (4.82 x 10^-6)/(8.85x10^-12)
=5.44 * 10^5 Nm^2/C
========
b) Electric flux through one face of the tetrahedron = (5.44*10^5)/4 = 1.36 *10^5 Nm^2/C
=========
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