Please help answer questions (a)-(c).
Solution:-
Mean = 100, S.D = 11
a) The percentage of people has an IQ score between 67 and 133 is 99.7%.
x1 = 67
x2 = 133
By applying normal distribution:-
z1 = -3
z2 = 3
P( -3.0 < z < 3.0) = 0.997
P( -3.0 < z < 3.0) = 99.7%
b) The percentage of people has an IQ score less than 67 and or greater than 133 is 0.3%.
x1 = 67
x2 = 133
By applying normal distribution:-
z1 = -3
z2 = 3
P( -3.0 > z > 3.0) = 1 - 0.997
P( -3.0 > z > 3.0) = 0.003
P( -3.0 > z > 3.0) = 0.3%
c) The percentage of people has an IQ score greater than 122 is 2.5%.
x = 122
By applying normal distribution:-
z = 2
P(z > 2) = (1 - 0.95)/2
P(z > 2) = 0.025
P(z > 2) = 2.5%
Please help answer questions (a)-(c). Objective 4: Use the Empirical Rule to Describe Data That Are...
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