Question

8. Draw the structure of 5-amino-3-bromo-3-methyl-2-heptanol. Classify the alcohol, amine and alkyl halide present in this structu re as primary, secondary and tertiary (1+3 points)

Answer 1

1) Amino group is Primary because the nitrogen is attached to only one carbon atom .(Primary amines have only one carbon bonded to nitrogen.)

1 H H-C-C-C- C 7 H 1 H H-C-K H HT H Primosuy Paimary amin I-UZ I-C-I

2) Alkylbromide group is Tertiary because carbon attached to bromine is further attached to three carbon atoms so the alkyl Bromide group is tertiary .

OH Br H H 1 1 H-C CC-C -C-H t H H-C- H H M H TertiaryAlkyl Bromide

3)Methyl group is Secondary because carbon attached to methyl group is further attached to two carbon atoms so the methyl group is secondary .

Br H H 1 H-C-C C C-C-C-C-H ои 1 H H H H H-C-H H Secondasuy Methyl 1--2 I-c-r

4) Alcohol group is Secondary because carbon attached to alcohol group is further attached to two carbon atoms so the alcohol group is secondary .

OH Br H H 1 C-C H C C-C-C-C t 1 1 H CH3 Secondary alcohet ター H I- C-H I-C-N I-C-r

Full picture

Tentiary Atkyl Bremide Secemdary Alechet OH B 1 H H 1 H-CICIC-C-CC- C-H 1 H I H-C-H H H Secondary Mettyl Primary amine I-CIH I-CI

Explaination

First right 7 carbons side-by-side because in the given name the parent chain contain 7 carbon due to the presence of hept in the name.

Number these carbons from left to right as 1 2 3 4 5 6 7

The Amino substituent is at 5th carbon of this carbon chain

The bromo substituent is present on the the 3rd carbon of this carbon chain

The methyl substituent is present at the 3rd carbon of this carbon Chain and

alcohol group is present at 2nd position and it is the functional group therefore written at the end of the name as 2-heptanol . (-ol is written to denote alcohol or hydroxyl group /OH^-)

After writing all the substituents and functional group Now add hydrogens to complete the valency of 4 of all the carbons .

エーUーエ エーUーエ I' 1--N エーUーエ . n I- - エーJーエ I I