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4. Write all necessary equations (Ka, Kb MB etc etc) needed to determine exactly the [H] of a 0.05M solution of Ca(HCOO)2 (ca
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Ka for HCOOH 3 1.8 х 104 Kb for HCOOH = Kw/Ka 1.0 x 10-14/(1.8 x 10-4 = 5.56 x 10-11 -----» Ca*2 (aq) + 2 HCOO (aq) Ca(HCOO)2

х.х К, 0.10 x = 5.56x10-11 x5.56x10lx-5.56x10-12 = 0 by solving we get, x 2.36x10 [OH x2.36x 10 Kw 1x10-14 4.24x10 M [H*= [OH

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