Ans 3
Concentration of NaBr = 0.05 M
The dissociation reaction of NaBr
NaBr = Na+ + Br-
Concentration of Br- = 0.05 M
In this solution PbBr2 is mixed
The dissociation reaction of PbBr2
PbBr2 = Pb2+ + 2Br-
Concentration of Br- = 2*0.05 = 0.10 M
Concentration of Pb2+ = 0.10 M
3. What is the concentration of Pb if PbBrais placed in a 0.05M solution of NaBr?...
PbBr2: 6.6*10^-6 3. What is the concentration of Pb if PbBris placed in a 0.05M solution of NaBr? (You may assume no complexes are formed.) 4. Write all necessary equations (Ka, Kb MB etc etc) needed to determine exactly the [H'] of a 0.05M solution of Ca(HCOO): (calcium formate). (Calcium formate is completely soluble in water and you can assume no Ca(OH)2 is formed. ) Ignore activites
3. What is the concentration of Pbl if PbBr is placed in a 0.05M solution of NaBr? [You may assume no complexes are formed.) Write all necessary equations (Ka, Kb MB etc etc) needed to determine exactly the [H') of a 0.05M solution of Ca(HCOO)2 (calcium formate). (Calcium formate is completely soluble in water and you can assume no Ca(OH)2 is formed. ) Ignore activites
4. Write all necessary equations (Ka, Kb MB etc etc) needed to determine exactly the [H] of a 0.05M solution of Ca(HCOO)2 (calcium formatel. (Calcium formate is completely soluble in water and you can assume no Ca(OH)2 is formed.) Ignore activites
pbbrzis placed in a 0.05M solution of NaBr? (You may 3. What is the concentration of Pbif PbBT assume no complexes are formed.)
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