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An automotive repair shop has determined that the average service time on an automobile is 2 hours with a standard deviation
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Answer #1

Solution:

(a) Given μ = 120, σ = s/√n = 32/√64 = 4
t(114) = 114-120/4 = -1.5
P(x̅ ≥ 114) = P(t ≥ -1.5 with df = 63) = 0.0693
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(b) Standard Error SE = 32/sqrt(400) = 1.6
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(c) t(110) = 110-120/1.6 = -6.25
P(x̅ ≥ 110) = P(t ≥ -6.25 with df = 63) = 0.00005

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