A candy company claims that 15% of its plain candies are orange, and a sample of...
A candy company claims that 15% of its plain candies are orange, and a sample of 100 such candies is randomly selected. a. Find the mean and standard deviation for the number of orange candies in such groups of 100. mu μ equals = 15 (Do not round.) sigma σ equals = nothing (Round to one decimal place as needed.)
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A candy company claims that 15% of its plain candies are
orange, and a sample of...
9) A candy company claims that 12% of its plain candies are orange, and a sample...
9) A candy company claims that 12% of its plain candies are orange, and a sample of 100 such candies is randomly selected. a. Find the mean and standard deviation for the number of orange candies in such groups of 100. μ =___________ (Do not round). σ=______________ (Round to one decimal place as needed). A random sample of 100 candies contains 16 orange candies. Is this result unusual? Does it seem that the claimed rate of 12% is wrong? A....
According to a candy company, packages of a certain candy contains 15% orange candies. Find the...
According to a candy company, packages of a certain candy contains 15% orange candies. Find the approximate probability that the random sample of 300 candies will contain 19% or more orange candies. Using a normal approximation, what is the probability that at least 19% of 300 randomly sampled candies will be orange?
Assume that adults have IQ scores that are normally distributed with a mean of mu equals...
Assume that adults have IQ scores that are normally distributed with a mean of mu equals 100 μ=100 and a standard deviation sigma equals 15 σ=15. Find the probability that a randomly selected adult has an IQ less than 121 The probability that a randomly selected adult has an IQ less than121 is ________. (Type an integer or decimal rounded to four decimal places as needed.)
Assume that a procedure yields a binomial distribution with n trials and the probability of success...
Assume that a procedure yields a binomial distribution with n trials and the probability of success for one trial is p. Use the given values of n and p to find the mean mu μ and standard deviation sigma σ. Also, use the range rule of thumb to find the minimum usual value mu minus 2 sigmas μ−2σ and the maximum usual value mu plus 2 sigma μ+2σ. n equals = 250 , p equals = 0.75 mu μ equals...
Kathy recorded the results for a sample of 502 candies. The candy company claims that the...
Kathy recorded the results for a sample of 502 candies.
The candy company claims that the distribution of each color is
exactly 20%.
Select the observed and expected frequencies for the red
candies.
Counts Color Red %ê) 24% 120 Yellow 106 21% Green 75 15% Orange 111 22% Purple 90 18%
The weights of a certain brand of candies are normally distributed with a mean weight of...
The weights of a certain brand of candies are normally distributed with a mean weight of 0.8549 g and a standard deviation of 0.052 g. A sample of these candies came from a package containing 452 candies, and the package label stated that the net weight is 386.1g. (If every package has 452 candies, the mean weight of the candies must exceed StartFraction 386.1 Over 452 EndFraction =0.8541 g for the net contents to weigh at least 386.1g.) a. If...
in a past election, the voter turnout was 62%. In a survey, 806 subjects were asked...
in a past election, the voter turnout was 62%. In a survey, 806 subjects were asked if they voted in the election. a. Find the mean and standard deviation for the numbers of voters in groups of 806. b. In the survey of 806 people, 498 said that they voted in the election. Is this result consistent with the turnout, or is this result unlikely to occur with a turnout of 62%? Why or why not? c. Based on these...
Sundrop candies inc claims that their 3 oz bag of candies contains 90 pieces of candy....
Sundrop candies inc claims that their 3 oz bag of candies contains 90 pieces of candy. A consumer group does not think this claim is accurate and obtains a random sample of 26, 3oz bags of the Sundrop candies. The number of candies in each bag is recorded: 89, 90, 84, 89, 91, 90, 87, 86, 93, 89, 89, 86, 87, 90, 89, 89, 90, 91, 88, 88, 87, 86, 91, 86, 86, 92 a) Find a 95% confidence interval...
Suppose a candy company representative claims that colored candies are mixed such that each large production...
Suppose a candy company representative claims that colored candies are mixed such that each large production batch has precisely the following proportions: 10% brown, 10% yellow, 30% red, 10% orange, 10% green, and 30% blue. The colors present in a sample of 458 candies was recorded. Is the representative's claim about the expected proportions of each color refuted by the data? Color brown yellow red orange green blue Number of Candies 110 92 64 87 41 64 Find the critical...
The weights of a certain brand of candies are normally distributed with a mean weight of...
The weights of a certain brand of candies are normally distributed with a mean weight of 0.8614 g and a standard deviation of 0.0511 g. A sample of these candies came from a package containing 447 candies, and the package label stated that the net weight is 381.4 g. (lf every package has 447 candies, the mean weight of the candies must exceed 381.4 0.8532 g for the net contents to weigh at least 381.4 g.) 447 a. If 1...
Kathy recorded the results for a sample of 502 candies.
The candy company claims that the distribution of each color is
exactly 20%.
Select the observed and expected frequencies for the red
candies.
Counts Color Red %ê) 24% 120 Yellow 106 21% Green 75 15% Orange 111 22% Purple 90 18%
The weights of a certain brand of candies are normally distributed with a mean weight of 0.8614 g and a standard deviation of 0.0511 g. A sample of these candies came from a package containing 447 candies, and the package label stated that the net weight is 381.4 g. (lf every package has 447 candies, the mean weight of the candies must exceed 381.4 0.8532 g for the net contents to weigh at least 381.4 g.) 447 a. If 1...
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