9) A candy company claims that 12% of its plain candies are orange, and a sample of 100 such candies is randomly selected.
a. Find the mean and standard deviation for the number of orange candies in such groups of 100.
μ =___________ (Do not round).
σ=______________ (Round to one decimal place as needed).
A random sample of 100 candies contains 16 orange candies. Is this result unusual? Does it seem that the claimed rate of 12%
is wrong?
A. Yes, because 16 is below the minimum usual value. Thus, the claimed rate of 12% is probably wrong.
B. No, because 16 is within the range of usual values. Thus, the claimed rate of 12% is not necessarily wrong.
C. Yes, because 16 is greater than the maximum usual value. Thus, the claimed rate of 12% is not necessarily wrong.
D. Yes, because 16 is within the range of usual values. Thus, the claimed rate of 12% is probably wrong.
a)
here mean of distribution=μ=np= | 12 | |
and standard deviation σ=sqrt(np(1-p))= | 3.2 |
B. No, because 16 is within the range of usual values. Thus, the claimed rate of 12% is not necessarily wrong.
9) A candy company claims that 12% of its plain candies are orange, and a sample...
A candy company claims that 15% of its plain candies are orange, and a sample of 100 such candies is randomly selected. a. Find the mean and standard deviation for the number of orange candies in such groups of 100. mu μ equals = 15 (Do not round.) sigma σ equals = nothing (Round to one decimal place as needed.)
Kathy recorded the results for a sample of 502 candies. The candy company claims that the distribution of each color is exactly 20%. Select the observed and expected frequencies for the red candies. Counts Color Red %ê) 24% 120 Yellow 106 21% Green 75 15% Orange 111 22% Purple 90 18%
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