Question
For A, the answers are not 1.34x10^13 & 5.23x10^9
For B, the answers are not 2.65x10^13 & 1.03x10^10.


Chapter 13, Problem 049 Suppose that a comet that was seen in 613 A.D. by Chinese astronomers was spotted again in year 1966.
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Answer #1

Time, T = 1966 - 613 = 1353 yrs x 365 x 86400 = 4.27 x 10^10 sec

A)

Using Kepler's law,

T^2 = (4 pi^2/GM) a^3

(4.27 x 10^10)^2 = (4 pi^2/6.67 x 10^-11 x 1.99 x 10^30) a^3

a = 1.83 x 10^13 m

B)

Maximum distance = a (e + 1)

D = 1.83 x 10^13 x (0.981 + 1) = 3.62 x 10^13 m

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