Time, T = 1966 - 613 = 1353 yrs x 365 x 86400 = 4.27 x 10^10 sec
A)
Using Kepler's law,
T^2 = (4 pi^2/GM) a^3
(4.27 x 10^10)^2 = (4 pi^2/6.67 x 10^-11 x 1.99 x 10^30) a^3
a = 1.83 x 10^13 m
B)
Maximum distance = a (e + 1)
D = 1.83 x 10^13 x (0.981 + 1) = 3.62 x 10^13 m
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For A, the answers are not 1.34x10^13 & 5.23x10^9 For B, the answers are not 2.65x10^13...
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