Question

physical chemistry, please show all work and explanations clearly

3. Consider the gaseous reaction 2 NOCI <=> 2 NO + Cl2 starting with pure NOCI. At 227°C the system reaches equilibium at a total pressure of 1 bar with a partial pressure of 0.64 bar for NOCI. a) What is the extent of reaction &? [0.136] b) What is the value of Kp? c) Determine AGPx for this reaction. d) What is the total pressure when the partial pressure of Cl2 is 0.1 bar? (note that & depends upon the total pressure) [0.787 bar]

Answer 1

At equilibrium co - QP P Given reaction : - Inockly) - 2Nolg) + Clelg) Initial pressuse / bar po - - Pressure Iban superma (po-2p) IP-2 As given in question, Atequilibrium, total pressure = 1 ban nie po- eff + 2P +P = 1 bar - potp.A - Also, Partial pressure of NOU = 0.64 bar. Pie p-2P = 0.64 - Subtracting eqn @ from ② gives 3p =0:36 0.24 TP: 0.12 bar ] and [po .0.88 bar ] 1. Thus, 200 cl) = 200 lg) + de 1g) initial Poessuvelbao 0.88 At eqbm Pl bar 0.64 0.12 1. (i) Extent of a reaction measure the extent in which the reaction proceeds. It is represented by Ę. & ni-ni where nis initial moles of species i ni = moles of species i since ne a p at time ť Vi : stoichiometoit coefficient

This, & = p - P where pl - Pressure at time t. Say in terms of Noc. f = POCNOC) - pi (nou) vi (Noul - 60.88 - 0164) E 0.12 bage in terms of no Es = POCNO) - PINO) 2 0.24 - 0 = la ona barl in terms of Cle le = P(cle) - P ((,) = 0.12 - 0 1 product | 2012 bala ii) kp is defined as the ratio of pressure of steactant species to the pressure of reactant species at equilibrium raise to power their stoichiometric coefficient. ke: 0.12 x 0.24 0.016876 0.64² I Kp = 1.69 x 10

1) AG = gibbs feree energy, which can be quelated to kp by AG = - RT dn ke . : -8.514 Th hot" x 500 K x ln (0.016875) IG : 16968.549 J molt lag: 16.97 kJ moto dno legs n allg) anocy z initial pressuse / been 0.88 (0.88-4p) đp P = 0.4 hou given in P=0.4 base raton question 0.88 - 20 top + P = Protal Plotal = 0.88 to 1 = 0.98 bar. - Protal = 0.98 ban T